Answer:
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4
Step-by-step explanation:
The slope is denoted by m and is calculated using the formula
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
The given vertices are:
A(-2,4) B(-1,1) C(2,3)
The sides will be:
AB, BC, AC
Let m1 be the slope of AB
Let m2 be the slope of BC
Let m3 be the slope of AC
Now
[tex]Slope\ of\ AB = m_1 = \frac{1-4}{-1+2} = \frac{-3}{1} = -3\\Slope\ of\ BC = m_2 = \frac{3-1}{2+1} = \frac{2}{3}\\Slope\ of\ AC = m_2 = \frac{3-4}{2+2} = \frac{-1}{4} = -\frac{1}{4}[/tex]
Hence,
The slopes of three sides of triangle are as follows:
AB = -3
BC = 2/3
AC = -1/4
