Respuesta :
Answer:
u = -5/9
General Formulas and Concepts:
Pre-Algebra
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
Step 1: Define equation
-3(u + 2) = 5u - 1 + 5(2u + 1)
Step 2: Solve for u
- Distribute: -3u - 6 = 5u - 1 + 10u + 5
- Combine like terms: -3u - 6 = 15u + 4
- Add 3u to both sides: -6 = 18u + 4
- Subtract 4 on both sides: -10 = 18u
- Divide 18 on both sides: -10/18 = u
- Simplify: -5/9 = u
- Rewrite: u = -5/9
Step 3: Check
Plug in u into the original equation to verify it's a solution.
- Substitute in u: -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
- Multiply: -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
- Add: -3(13/9) = -25/9 - 1 + 5(-1/9)
- Multiply: -13/3 = -25/9 - 1 - 5/9
- Subtract: -13/3 = -34/9 - 5/9
- Subtract: -13/3 = -13/3
Here we see that -13/3 does indeed equal -13/3.
∴ u = -5/9 is a solution of the equation.
Answer:
[tex] \sf u = -\dfrac{5}{9} [/tex]
Step-by-step explanation:
Expand the following:
[tex] \longrightarrow [/tex] -3(u + 2) = 5u - 1 + 5(2u + 1)
5(2u + 1) = 10u + 5:
[tex] \longrightarrow [/tex] -3(u + 2) = 5u - 1 + 10u + 5
-3(u + 2) = -3u - 6:
[tex] \longrightarrow [/tex] -3u - 6= 10 u + 5 u - 1 + 5
Grouping like terms,
5u - 1 + 10u + 5 = (5u + 10u) + (-1 + 5):
[tex] \longrightarrow [/tex] -3u - 6 = (5u + 10u) + (-1 + 5)
5u + 10u = 15u:
[tex] \longrightarrow [/tex] -3u - 6 = 15u + (-1 + 5)
5 - 1 = 4:
[tex] \longrightarrow [/tex] -3u - 6 = 15u + 4
Subtract 15 u from both sides:
[tex] \longrightarrow [/tex] (-3u - 15u) - 6 = (15u - 15u) + 4
-3u - 15u = -18u:
[tex] \longrightarrow [/tex] -18u - 6 = (15u - 15u) + 4
15u - 15u = 0:
[tex] \longrightarrow [/tex] -18u - 6 = 4
Add 6 to both sides:
[tex] \longrightarrow [/tex] (6 - 6) - 18u = 6 + 4
6 - 6 = 0:
[tex] \longrightarrow [/tex] -18u = 4 + 6
4 + 6 = 10:
[tex] \longrightarrow [/tex] -18u = 10
Divide both sides of -18 u = 10 by -18:
[tex] \longrightarrow [/tex] [tex] \sf \dfrac{-18u}{-18}= \dfrac{10}{-18} [/tex]
[tex] \sf \dfrac{-18}{-18}=1: [/tex]
[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{10}{-18} [/tex]
[tex] \sf \dfrac{10}{-18}=\dfrac{5}{-9}: [/tex]
[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{5}{-9} [/tex]
Multiply numerator and denominator of [tex] \sf \dfrac{10}{-18} [/tex] by -1:
[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{-5}{9} [/tex]