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Answer:

u = -5/9

General Formulas and Concepts:

Pre-Algebra

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

Step 1: Define equation

-3(u + 2) = 5u - 1 + 5(2u + 1)

Step 2: Solve for u

  1. Distribute:                             -3u - 6 = 5u - 1 + 10u + 5
  2. Combine like terms:             -3u - 6 = 15u + 4
  3. Add 3u to both sides:          -6 = 18u + 4
  4. Subtract 4 on both sides:    -10 = 18u
  5. Divide 18 on both sides:      -10/18 = u
  6. Simplify:                                -5/9 = u
  7. Rewrite:                                 u = -5/9

Step 3: Check

Plug in u into the original equation to verify it's a solution.

  1. Substitute in u:                     -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
  2. Multiply:                                -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
  3. Add:                                      -3(13/9) = -25/9 - 1 + 5(-1/9)
  4. Multiply:                                -13/3 = -25/9 - 1 - 5/9
  5. Subtract:                               -13/3 = -34/9 - 5/9
  6. Subtract:                               -13/3 = -13/3

Here we see that -13/3 does indeed equal -13/3.

∴ u = -5/9 is a solution of the equation.

Answer:

[tex] \sf u = -\dfrac{5}{9} [/tex]

Step-by-step explanation:

Expand the following:

[tex] \longrightarrow [/tex] -3(u + 2) = 5u - 1 + 5(2u + 1)

5(2u + 1) = 10u + 5:

[tex] \longrightarrow [/tex] -3(u + 2) = 5u - 1 + 10u + 5

-3(u + 2) = -3u - 6:

[tex] \longrightarrow [/tex] -3u - 6= 10 u + 5 u - 1 + 5

Grouping like terms,

5u - 1 + 10u + 5 = (5u + 10u) + (-1 + 5):

[tex] \longrightarrow [/tex] -3u - 6 = (5u + 10u) + (-1 + 5)

5u + 10u = 15u:

[tex] \longrightarrow [/tex] -3u - 6 = 15u + (-1 + 5)

5 - 1 = 4:

[tex] \longrightarrow [/tex] -3u - 6 = 15u + 4

Subtract 15 u from both sides:

[tex] \longrightarrow [/tex] (-3u - 15u) - 6 = (15u - 15u) + 4

-3u - 15u = -18u:

[tex] \longrightarrow [/tex] -18u - 6 = (15u - 15u) + 4

15u - 15u = 0:

[tex] \longrightarrow [/tex] -18u - 6 = 4

Add 6 to both sides:

[tex] \longrightarrow [/tex] (6 - 6) - 18u = 6 + 4

6 - 6 = 0:

[tex] \longrightarrow [/tex] -18u = 4 + 6

4 + 6 = 10:

[tex] \longrightarrow [/tex] -18u = 10

Divide both sides of -18 u = 10 by -18:

[tex] \longrightarrow [/tex] [tex] \sf \dfrac{-18u}{-18}= \dfrac{10}{-18} [/tex]

[tex] \sf \dfrac{-18}{-18}=1: [/tex]

[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{10}{-18} [/tex]

[tex] \sf \dfrac{10}{-18}=\dfrac{5}{-9}: [/tex]

[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{5}{-9} [/tex]

Multiply numerator and denominator of [tex] \sf \dfrac{10}{-18} [/tex] by -1:

[tex] \longrightarrow [/tex] [tex] \sf u = \dfrac{-5}{9} [/tex]

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