Question

A particular solution of hydrochloric acid is 3.0 M. How many moles of hydrochloric acid are present in 22.7 mL of this solution?

Answer 1

Answer:

0.0681 HCl moles

Explanation:

First we convert 22.7 mL to liters:

• 22.7 mL * $\frac{1L}{1000mL}$ = 0.0227 L

Then we use the definition of molarity:

• molarity = moles / liters

• moles = molarity * liters

• moles = 3.0 M * 0.0227 L

• moles = 0.0681 moles

So there are 0.0681 hydrochloric acid moles in 22.7 mL of a 3.0 M HCl solution.