The magnitude and direction angle of c is 12.8 and 128.7° respectively.
"A vector contains two types of information: a magnitude and a direction. The magnitude is the length of the vector while the direction tells us which way the vector points.
Vector direction can be given in various forms, but is most commonly denoted in degrees. Acceleration and velocity are examples of vectors."
Given: a = (5, –9) and b = (–3, 1) and c = b – a.
Therefore, c = (5+3, -9-1) = (8, -10)
Now, magnitude of c is [tex]\sqrt{8^{2}+(-10)^{2}}[/tex] = 12.8
The direction of c is Ф = tan⁻¹(-10/8) = -51.3°
Therefore, the direction of c is 180° - 51.3° = 128.7° (tanФ = tan(π+Ф))
Learn more about magnitude and direction of a point here: https://brainly.com/question/11864438
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