Question

Nov 27, 8:06:26 PM
Find the Area of the figure below, composed of a rectangle and a semicircle. Round to
the nearest tenths place.
14
10
Answer:
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Answer 1

Answer:

The area of given figure is: 179.3

Step-by-step explanation:

The figure consists of a rectangle and a semi-circle

The length of rectangle is 14 and width is 10.

The width of rectangle is also the diameter of the semi-circle.

So,

d = 10

$r = \frac{d}{2} = \frac{10}{2} = 5$

Area of Semi-Circle:

$C =\frac{ \pi r^2}{2}\\= \frac{3.14 * (5)^2}{2}\\=\frac{3.14*25}{2}\\=\frac{78.5}{2}\\= 39.25$

Area of Rectangle:

$R = Length * Width\\R = 10*14\\R = 140$

The total area will be the sum of area of rectangle and the area of semi-circle

So,

$Total\ Area = C + R\\= 39.25 + 140\\=179.25$

Rounding off to nearest tenth

The total area is: 179.3