Option E will be the correct option.
Condition for the balanced hanger,
- Both the sides of the hanger will be balanced if weights on both the sides of the hanger must be equal.
Weights on left side = 4(weight of one square) + 2(weight of one triangle) + 2(weight of one circle)
Weights on right side = 2(weight of one square) + 1(weight of one triangle) + 3(weight of one circle)
Since, hanger is balanced,
Weights on the left side = Weights on the right side
4(weight of one square) + 2(weight of one triangle) + 2(weight of one circle) = 2(weight of one square) + 1(weight of one triangle) + 3(weight of one circle)
4x + 2(2.5) + 2(3) = 2x + 2.5 + 3(3)
4x + 2.5 + 2.5 + 3 + 3 = 2x + 2.5 + 3 + 3 + 3
Therefore, Option E will be the answer.
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