Answer:
0.0023 cm
Explanation:
The following data were obtained from the question:
Length (L) = 55 cm
Breadth (B) = 23.3 cm
Volume (V) = 2.9 cm³
Thickness (T) =?
Thus, we can obtain the thickness of the aluminum foil as illustrated below:
V = L × B × T
2.9 = 55 × 23.3 × T
2.9 = 1281.5 × T
Divide both side by 1281.5
T = 2.9/1281.5
T = 0.0023 cm
Therefore, the thickness of the aluminum foil is 0.0023 cm
