Answer:
The value of Equilibrium constant for the given reaction is 0.089
Explanation:
The given data shows the following reaction
H2O (g) + Cl2O (g) ⇄ 2 HClO (g)
The above reaction is in equilibrium.
Equilibrium constant K = [tex]\frac{[C]^c*[D]^d}{[A]^a*[B]^b}[/tex]
for the reaction
aA+bB ⇆ cC +dD
so
K = [tex]\frac{[HClO]^2}{[H2O][Cl2O]}[/tex]
= [tex]\frac{[0.023]^2}{[0.077][0.077]}[/tex] = 23*23/77*77 = 0.089
Therefore the value of Equilibrium constant for the given reaction is 0.089
Answer:
The value of Equilibrium constant for the given reaction is 0.089