Question

1. A particular lever is 90.0% efficient. If 50.0 J of work are done on the lever, then how much work does the lever do on its load? 2.The mechanical advantage of a pulley system is 4.00. Using this pulley system, how much force do you need to exert to lift a 500.0 N box?

Answer 1

Answer:

Explanation:

Using the efficiency formula;

Efficiency = Work done by the machine (output)/work done on the machine (input) ×100%

Efficiency =w/50 ×100

90 = 100w/50

Cross multiply

90×50 = 100W

4500 = 100W

W = 4500/100

W = 45Joules

Hence the lever does 45Joules of work on its load

2) Mechanical Advantage= Load/Effort

Given

MA = 4

Load = 500N

4 = 500/Effort

Effort = 500/4

Effort =125N

Hence the effort required to lift the load is 125N

Answer 2

1. The work done by the lever on its load is 45 J

2. The force needed to exert to lift the load is 125 N.

1. Determination of the work done by the lever on the load.

Work Input = 50 J

Efficiency = 90%

Work Output =?

$efficiency \: = \frac{work \: output}{work \: input} \times 100 \\ \\ 90\% = \frac{work \: output}{50} \\ \\ cross \: multiply \\ \\ work \: output \: = 90\% \: \times 50 \\ \\ work \: output = 0.9 \: \times 50$

Work Output = 45 J

Therefore, the work done by the lever on the load is 45 J

2. Determination of the force needed to lift the load

Mechanical advantage (MA) = 4

Load (L) = 500 N

Effort (E) = ?

$mechanical \: advantage \: = \frac{load}{effot} \\ \\ 4 \: = \frac{500}{effort} \\ \\ cross \: multiply \\ \\ 4 \: \times effort \: = 500 \\ \\ divide \: both \: side \: by \: 4 \\ \\ effort \: = \frac{500}{4}$

Effort = 125 N

Therefore, the force needed to lift the load is 125 N

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