Question

If y =9x^4 - x^3 / x^2 , then dy/dx is:
Someone please help

Answer 1

Answer:

$\frac{dy}{dx} = 18x - 1$

Step-by-step explanation:

$y = \frac{9x^{4} - x^{3}}{x^{2} }\\\\y = \frac{9x^{4}}{x^{2} } - \frac{x^{3}}{x^{2} } \\\\y = 9x^{2} - x\\\\\frac{dy}{dx} = 18x - 1$