Question

3. Ms. Turner's garden has side lengths of V17 yards and V24 yards.

Mr. Webster's garden has side lengths of V5 yards and 138 yards.

Compare the areas of the gardens. Decide whose garden is larger and by how much. Be sure to

explain your thinking. (A = lw)

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10:04 PS

Answer 1

Answer:

Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.

Step-by-step explanation:

Representing the length of the garden by l and width of the garden by w.

For turner's garden, given that l= 24 yards and w= 17 yards.

As the area, A, of the rectangular garden having  length l and width w is

So, the area of Ms. Turner's garden, = 24x17=408 sq. yards

For turner's garden, given that l= 5 yards and w= 138 yards.

So, by using equation (i),

the area of Mr. Webster's garden, = 5x138=690 sq. yards

Here, $A_2 > A_1$, and  

= 690-408= 282 sq. yards.

Hence, Mr. Webster's garden is greater than Ms. Turner's garden by 282 sq. yards.