) Multiply (x − 4)(x2 − 5x − 6). x3 − 9x2 + 14x + 24 x3 − x2 + 26x + 24 x3 − 5x2 + 10x + 24 x3 − 15x2 + 20x + 24 Question 10(Multiple Choice Worth 6 points) (01.03 MC) Solve for all possible values of x. square root of the quantity x minus 8 end quantity minus 3 equals 1 x = −4 x = 8 x = 12 x = 24

Respuesta :

9514 1404 393

Answer:

  A.  x^3 − 9x^2 + 14^x + 24

Step-by-step explanation:

(x − 4)(x^2 − 5x − 6) = x(x^2 − 5x − 6) -4(x^2 − 5x − 6)

  = x^3 -5x^2 -6x -4x^2 +20x +24

  = x^3 +x^2(-5-4) +x(-6+20) +24

  = x^3 − 9x^2 + 14x + 24 . . . . matches the first choice

Answer:

The other person is right it is "x^3 − 9x^2 + 14x + 24"

Step-by-step explanation:

They showed their work so i felt like u could just look at theirs!!!

Xoxo

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