Answer:
x = 50 mph speed of the bus
y = 75 mph speed of the train
Step-by-step explanation:
Lt´s call "x" speed of bus and "y" speed of train.
According to the problem statement
6*x = 4*y (1)
y = x + 25 (2)
We solve for x and y the two equation system
y = ( 6/4)*x
( 6/4)*x = x + 25
6*x = 4*x + 100
2*x = 100
x = 50 mph
And
y = (6/4)*x
y = 300/4
y = 75 mh