Question

A carnival ride consists of four circular cars - a b c d - each of which spins about at its center point The center points of cars a and b are attached by a straight beam as are the center points of c and d The 2 beams are attached at their midpoints by a rotating arm. A plan for the ride uses coordinate plane in which each unit represents one meter. In the plan, the center of car A (-6,-1) and B (-2,-3) and C (3,4) and D (5,0). Each car has a 3m diameter

Answer 1

Answer:

Hello your question is incomplete attached below  is the complete question

Answer : The shape of the fence will be a circle

              dimensions of the fence are : radius = 6.5 meters

Step-by-step explanation:

First we calculate the length of the different arms

AB = $\sqrt{(-2+6)^2 + (-3+1)^2}$

     ≈ 4.47

CD = $\sqrt{(5-3)^2 + (0-4)^2}$

     ≈ 4.47

Next we calculate the midpoint of these two arms

M1 = $( \frac{-6-2}{2} , \frac{-1-3}{2} )$ = ( -4, -2 )

M2 = $( \frac{3+5}{2} , \frac{0+4}{2} )$  = ( 4,2 )

hence midpoint of M1,M2 =( M ) = ( 0,0 )

finally considering M calculate the distance between M and car B,D

MB = $\sqrt{(0+2)^2 + (0+3)^2}$  = 3.60

MD = $\sqrt{(0-5)^2 + (0)^2}$  = 5

therefore the radius of the fence will be

= 5 + 1.5 = 6.5 meters ( because MD > MB )