Question

find the square of ( b - 9 )

Answer 1

Answer:

${b}^{2} - 18b + 81$

Step-by-step explanation:

${(b - 9)}^{2} = {b}^{2} - 2 \times b \times 9 + {(9)}^{2} \\ = {b}^{2} - 18b + 81$