Answer:
The solutions to the system of equations will be:
[tex]y=6,\:x=0[/tex]
Step-by-step explanation:
Given the equation
[tex]-6y+11x=-36[/tex]
[tex]-4y+7x=-24[/tex]
solving the system of equations
[tex]\begin{bmatrix}-6y+11x=-36\\ -4y+7x=-24\end{bmatrix}[/tex]
[tex]\mathrm{Multiply\:}-6y+11x=-36\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-12y+22x=-72[/tex]
[tex]\mathrm{Multiply\:}-4y+7x=-24\mathrm{\:by\:}3\:\mathrm{:}\:\quad \:-12y+21x=-72[/tex]
[tex]\begin{bmatrix}-12y+22x=-72\\ -12y+21x=-72\end{bmatrix}[/tex]
[tex]-12y+21x=-72[/tex]
[tex]-[/tex]
[tex]\underline{-12y+22x=-72}[/tex]
[tex]-x=0[/tex]
[tex]\begin{bmatrix}-12y+22x=-72\\ -x=0\end{bmatrix}[/tex]
solving for x
[tex]-x=0[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}-1[/tex]
[tex]\frac{-x}{-1}=\frac{0}{-1}[/tex]
[tex]x=0[/tex]
[tex]\mathrm{For\:}-12y+22x=-72\mathrm{\:plug\:in\:}x=0[/tex]
[tex]-12y+22\cdot \:0=-72[/tex]
[tex]-12y+0=-72[/tex]
[tex]-12y=-72[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}-12[/tex]
[tex]\frac{-12y}{-12}=\frac{-72}{-12}[/tex]
[tex]y=6[/tex]
Therefore, the solutions to the system of equations will be:
[tex]y=6,\:x=0[/tex]
