Respuesta :

You did not clearly mention the second function. So, I am assuming you meant to say that the second function has the table values such as:

x           y

0           4

-2          2

So, I am solving the question based on this information table of the 2nd function, which anyways will clear your concept.

Answer:

We conclude that the rate of change of a function '1' is greater than the rate of change of function '2'.

Step-by-step explanation:

Given the function 1

[tex]y = 2x + 6[/tex]

Comparing the function with the slope-intercept form of the line equation of a linear function

  • [tex]y=mx+b[/tex]

where m is the rate of change or slope of the line

so

[tex]y = 2x + 6[/tex]

rate of change = m = 2

Now, given the function 2

x           y

0           4

-2          2

Taking the slope of the two points in the table

(0 4), (-2, 2)

[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\left(x_1,\:y_1\right)=\left(0,\:4\right),\:\left(x_2,\:y_2\right)=\left(-2,\:2\right)[/tex]

[tex]m=\frac{2-4}{-2-0}[/tex]

[tex]m=1[/tex]

So, the rate of change or slope of the function 2 is: m = 1

Hence, we observe that:

  • Rate of change of function 1 = m = 2
  • Rate of change of function 2 = m = 1

As the rate of change of a function '1' is greater than the rate of change of function 2.

i.e.

m = 2 > m = 1

Therefore, we conclude that the rate of change of a function '1' is greater than the rate of change of function '2'.

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