You did not clearly mention the second function. So, I am assuming you meant to say that the second function has the table values such as:
x y
0 4
-2 2
So, I am solving the question based on this information table of the 2nd function, which anyways will clear your concept.
Answer:
We conclude that the rate of change of a function '1' is greater than the rate of change of function '2'.
Step-by-step explanation:
Given the function 1
[tex]y = 2x + 6[/tex]
Comparing the function with the slope-intercept form of the line equation of a linear function
where m is the rate of change or slope of the line
so
[tex]y = 2x + 6[/tex]
rate of change = m = 2
Now, given the function 2
x y
0 4
-2 2
Taking the slope of the two points in the table
(0 4), (-2, 2)
[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:4\right),\:\left(x_2,\:y_2\right)=\left(-2,\:2\right)[/tex]
[tex]m=\frac{2-4}{-2-0}[/tex]
[tex]m=1[/tex]
So, the rate of change or slope of the function 2 is: m = 1
Hence, we observe that:
As the rate of change of a function '1' is greater than the rate of change of function 2.
i.e.
m = 2 > m = 1
Therefore, we conclude that the rate of change of a function '1' is greater than the rate of change of function '2'.