Question

At 6 atmosphere pressure, the volume of a gas is 1200 ml. What pressure is
required to reduce the volume of a gas to 200 ml without changing the
temperature?

Answer 1

Answer:

36 atm

Explanation:

The pressure required can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the required pressure

$P_2 = \frac{P_1V_1}{V_2}$

From the question we have

$P_2 = \frac{6 \times 1200}{200} = \frac{7200}{200} = \frac{72}{2}$

We have the final answer as

36 atm

Hope this helps you