Question

An electric circuit, powered by a voltage of 100 V, absorbs a power of 4.41 kW; calculate the intensity of the current that runs through the circuit and the energy absorbed by it in 2 hours and 15 minute​

Answer 1

Answer:

I = 44.1[amp]

P = 9.92 [kw-hr]

Explanation:

We know that electrical power can be calculated by means of the following expression.

$P=V*I$

where:

P = power = 4.41 [kW] = 4410 [w]

V = 100 [V]

I = current [amp]

Now we have:

$I=P/V\\I = 4410/100\\I = 44.1 [amp]$

Now the power absorbed during this time is equal to the product of power by time.

$15[min]*\frac{1hr}{60min} =0.25 [hr]$

t = time = 2.25 [hr]

$P_{ab}=4.41*2.25\\P=9.92[kW-hr]$