Question

FePO4 + Na2SO4  Fe2(SO4)3 + Na3PO4
If you perform this reaction with 24 grams of FePO4 and an excess Na2SO4, how many grams of Fe2(SO4)3 can you make?

Answer 1

Mass Fe₂(SO₄)₃ : 31.79 g

Further explanation

Reaction

2FePO₄ + 3Na₂SO₄ ⇒ Fe₂(SO₄)₃ + 2Na₃PO₄

mol FePO₄ (MW=150,82 g/mol) :

$\tt \dfrac{24}{150.82}=0.159$

mol  Fe₂(SO₄)₃ : mol FePO₄ = 1 : 2, so mol Fe₂(SO₄)₃ :

$\tt \dfrac{1}{2}\times 0.159=0.0795$

mass Fe₂(SO₄)₃ (MW=399,88 g/mol) :

$\tt 0.0795\times 399,88 g/mol=31.79~g$