legaspidrea
legaspidrea
27-11-2020
Mathematics
contestada
Solve for x
4/7^5x=64/343^2x-1
Respuesta :
noahaceja
noahaceja
27-11-2020
Answer:
4/7^5x=64/343^2x-1
(4/7)^5x=(4/7)^6x-3
5x=6x-3
5x-6x=-3
-x=-3
x=3
Hope this helps.
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