What is the voltage drop across the 10.0 2 resistor?
10.00
120.0 V
20.00
30.00
Answer: 20.0V

The voltage drop across the 10.0-ohm resistor would be 20.0 volt.
Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.
V=IR
For calculating equivalent resistance in series combination.
Re = R1 + R2 + R3
For the given problem the total resistance of the circuit would be as all the three resistors are connected in the series combination.
Re= 10+20+30
Re=60 ohm
As given in the figure all the resistance are connected in the series combination therefore the current flowing through them would be the same.
For the given problem we have to design and construct a circuit that has two resistors connected in series.
By using Ohms law
V=IR
120 = 60×I
I = 2 ampere
Given that we have a 120 V battery, that will produce a current of 2 Ampere
By using Ohm's law we can calculate the voltage drop across a 10-ohm resistor
V=IR
=2×10
= 20 volt
Thus, the voltage drop across the 10.0-ohm resistor comes out to be 20.0 volt.
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