Question

B is the midpoint of AC and D is the midpoint of CE. Solve for x,
given BD - 3x + 3 and AE = 5x + 11.
PLEASE HELP FOR GEOMETRY

Answer 1

Step-by-step explanation:

Required Answer:-

ATQ

${:}\longrightarrow$$\sf 2BD=AE$

${:}\longrightarrow$$\sf 2 (-3x+3)=5x+11$

${:}\longrightarrow$$\sf -6x+6=5x+11$

${:}\longrightarrow$$\sf -6x-5x=11-6$

${:}\longrightarrow$$\sf -11x=5$

${:}\longrightarrow$$\sf x={\dfrac {5}{-11}}$

Answer 2

9514 1404 393

Answer:

  x = 5

Step-by-step explanation:

Midline BD is half the length of base AE, so we have ...

  2BD = AE

  2(3x +3) = 5x +11

  6x +6 = 5x +11 . . . eliminate parentheses

  x = 5 . . . . . . . . . subtract 5x+6