Question

A function has f''(x) = 10 and has f'(4) = 0 and f(2) = 4. Find f(x)

Answer 1

Answer:

f(x) = 5x^2 - 40x + 64

Step-by-step explanation:

f''(x) = 10

f'(x) = 10x + a

f'(4) = 0 = 10*4 + a

a = -40

So f'(x) = 10x - 40

f(x) = 5x^2 - 40x + b

f(2) = 4 = 5*2^2 - 40*2 + b

4 = 20 - 80 + b

b = 64