Question

How many liters of a 3.89 M K2SO4 solution are needed to provide 99.8 g of K2SO4 (molar mass 174.01 g/mol)

Answer 1

Explanation:

anor277

Nov 17, 2017

Well, by definition,

Molarity

≡

Moles of solute

Volume of solution

Explanation:

And thus...

moles of solute

=

molarity

×

volume

We use a molar quantity of

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

=

0.461

⋅

m

o

l

with respect to

potassium sulfate

And thus

volume

=

moles of solute

molarity

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

3.12

⋅

m

o

l

⋅

L

−

1

=

0.148

⋅

L

.