Question

Current 1 of 8.4 A runs for 240 seconds and then stops. Current 2 is 10.5 A. How long does current 2 have to run to deliver the same amount of charge as current 1?

Answer 1

Current 1: 8.4 * 240 = 2,016 A delivered.

Current 2: 10.5 * t = 2,016
Divide each side by 10.5
t = 192

Current 2 needs to run 192 seconds to deliver the same amount of charge as current 1

Answer 2

This question involves the concepts of current and charge.

Current 2 has to run for "192 s" to deliver the same amount of charge as current 1.

Current

The current is defined as the amount of charge passing per unit time. Mathematically,

$I=\frac{q}{t}\\\\q = It$

Since, the charge for both the currents is same:

q₁ = q₂

I₁t₁ = I₂t₂

$t_2=\frac{I_1t_1}{I_2}$

where,

I₁ = current 1 = 8.4 A

I₂ = current 2 = 10.5 A

t₁ = time for current 1 = 240 s

t₂ = time for current 2 = ?

Therefore,

$t_2=\frac{(8.4\ A)(240\ s)}{10.5\ A}$

t₂ = 192 s

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