Question

Find the equation of the straight line line passing through the point ( 0 , 1 ) which is perpendicular to the line y = -2x + 2

Answer 1

Step-by-step explanation:

y=-2x+2

hence the gradient is -2

gradient of perpendicular line

m1m2=-1

-2m2=-1

2m2=1

m2=1/2

so equation when m=1/2

m(x-x1)=y-y1

0.5(x-0)=y-1

0.5x-0=y-1

0.5x+1=y hence this is the equation