The volume of NaOH that would be needed to reach the equivalence point is : 19 mL
Given data
volume of HCL = 50 mL = 0.05 L
conc of HCL = 0.100 M
volume of NaOH = ?
conc of NaOH = 0.100 M
New conc of added base = 0.270 M
At equivalence ;
moles of OH⁻ ions = moles of H⁺ ions
0.05 * 0.1 = 0.27 * v
therefore the volume ( v ) = ( 0.05 * 0.1 ) / 0.27
= 0.019 L = 19 mL
Hence we can conclude that The volume of NaOH that would be needed to reach the equivalence point is : 19 mL .
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