Question

Find the wavelength of light that has its third minimum at an angle of 48.6º when it falls on a single slit of width 3.00 μm .

Answer 1

Answer:

750 nm

Explanation:

It is given that,

Third minimum is at an angle of 48.6º when it falls on a single slit of width 3.00 μm.

We need to find the wavelength of the light. For a single slit experiment, the relation between wavelength and slit width is given by :

$d\sin\theta=n\lambda$

For third minimum, n = 3

$\lambda=\dfrac{d\sin\theta}{n}\\\\\lambda=\dfrac{3\cdot10^{-6}\cdot\sin48.6}{3}\\\\\lambda=7.5\times 10^{-7}\ m\\\\\lambda=750\ nm$

So, the wavelength of light is 750 nm.