Respuesta :

Abu99

Answer:

[tex](8\sqrt{15}).b^{\frac{9}{2} }[/tex]

Step-by-step explanation:

[tex]\sqrt{24b^{3} } . \sqrt{40b^{2} } .b^{2} = (\sqrt{24})b^{\frac{3}{2} } . (\sqrt{40})b. b^{2} \\\\= (\sqrt{24.40}).b^{\frac{3}{2} + 1 +2} \\\\= \sqrt{960} .b^{\frac{9}{2} } \\\\= 8\sqrt{15}.b^{\frac{9}{2} }[/tex]

Answer:

8b^3\sqrt[15b]

Step-by-step explanation:

I did it on Khan Academy

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