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A car initially traveling at 25 m/s speeds up to 60 m/s under a uniform acceleration of 5.0 m/s2 to avoid being hit by another car. How long does it take the car to speed up and get out of the way? Show your work.

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Answer:

The car takes 7 seconds to speed up and get out of the way

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly over time.

Having a as the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

v_f=v_o+at

Using the above equation we can solve for t:

[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]

The car has an initial speed of vo=25 m/s and ends up at vf=60 m/s with an acceleration of a=5 [tex]m/s^2[/tex].

Given all the appropriate data, calculate t:

[tex]\displaystyle t=\frac{60-25}{5}[/tex]

Calculating:

[tex]\displaystyle t=\frac{35}{5}[/tex]

t = 7 seconds

The car takes 7 seconds to speed up and get out of the way

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