Question

If the speed of an object in uniform circular motion is constant and the radial distance is doubled, by what factor does the magnitude of the radial acceleration decrease?

Answer 1

clean and healthy

Explanation:

Because you will smell

Answer 2

Answer: Half

Explanation:

Given

The object is in uniform circular motion with constant speed.

Radial acceleration of the object is given by

$\Rightarrow a_r=\dfrac{v^2}{r}$

Where, $a_r=\text{Radial acceleration}$

$v=\text{speed}\\r=\text{distance from the axis of rotation}$

If the radial distance $r$ is doubled, i.e. $2r$

Radial acceleration is

$\Rightarrow a'_r=\dfrac{v^2}{2r}\\\\\Rightarrow a'_r=\dfrac{a_r}{2}$

Radial acceleration becomes half of the initial value.

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