Answer:
Step-by-step explanation:
1). For a point (0, -15),
Here x = 0, so the piece of function that applies,
f(x) = 4x - 15 (Since, x = 0 lies in the range -2 ≤ x < 4)
= 4(0) - 15
= -15
True.
2). Since, f(x) = [tex]-\frac{1}{4}x^{2}+6x+36[/tex] for x < -2
= 4x - 15 for -2 ≤ x < 4
Which shows a gap between these graphs.
Therefore, graph has a discontinuity at x = -2
True.
3). For x > 4,
f(x) = [tex]3^{x-4}[/tex]
For every input value of x in the interval (4, ∞), output values of the function will be increasing.
So this option is TRUE.
4). In the interval (-12, -2),
Function to be followed → f(x) = [tex]-\frac{1}{4}x^{2}+6x+36[/tex]
Graph of the given quadratic function opens downwards (Since, coefficient of x² is negative).
In this graph value of function first increases then decreases.
So the answer is FALSE.
5). Since, input values of the function 'f' varies from (-∞, ∞)
Therefore, domain of the function will be (-∞, ∞)
TRUE.
