Respuesta :

Space

Answer:

60.0 mL

General Formulas and Concepts:

Chemistry - Solutions

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

Step 1: Define

6.33 g CuNO₃

0.840 M Solution

Step 2: Identify Conversions

1 L = 1000 mL

Molar Mass of Cu - 63.55 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CuNO₃ - 63.55 + 14.01 + 3(16.00) = 125.56 g/mol

Step 3: Convert

[tex]6.33 \ g \ CuNO_3(\frac{1 \ mol \ CuNO_3}{125.56 \ g \ CuNO_3} )[/tex] = 0.050414 mol CuNO₃

Step 4: Find volume

  1. Substitute:                              0.840 M = 0.050414 mol / x L
  2. Multiply x on both sides:       (x L)(0.840 M) = 0.050414 mol
  3. Divide M on both sides:         x L = 0.060017

Step 5: Convert

[tex]0.060017 \ L(\frac{1000 \ mL}{1 \ L} )[/tex] = 60.0168 mL

Step 6: Check

We are given 3 sig figs. Follow sig fig rules and round.

60.0168 mL ≈ 60.0 mL

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