What’s the volume of the solution?

Answer:
60.0 mL
General Formulas and Concepts:
Chemistry - Solutions
Explanation:
Step 1: Define
6.33 g CuNO₃
0.840 M Solution
Step 2: Identify Conversions
1 L = 1000 mL
Molar Mass of Cu - 63.55 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CuNO₃ - 63.55 + 14.01 + 3(16.00) = 125.56 g/mol
Step 3: Convert
[tex]6.33 \ g \ CuNO_3(\frac{1 \ mol \ CuNO_3}{125.56 \ g \ CuNO_3} )[/tex] = 0.050414 mol CuNO₃
Step 4: Find volume
Step 5: Convert
[tex]0.060017 \ L(\frac{1000 \ mL}{1 \ L} )[/tex] = 60.0168 mL
Step 6: Check
We are given 3 sig figs. Follow sig fig rules and round.
60.0168 mL ≈ 60.0 mL