Question

A ball is thrown with initial velocity 20 meter per second by making an angle 30 degree with a horizontal then find time of flight.

Answer 1

Answer:

$\huge\boxed{\sf T = 2.04\ secs}$

Explanation:

Given Data:

Initial Velocity = $\sf V_{i}$ = 20 m/s

Angle = $\sf \theta$ = 30°

Acceleration due to gravity = g = 9.8 m/s²

Required:

Time of flight = T = ?

Formula:

$\sf T = \frac{2\ V_{i}\ sin\theta}{g}$

Solution:

Putting values in the above formula

T = 2(20)sin 30 / 9.8

T = 40 (0.5) / 9.8

T = 20 / 9.8

T = 2.04 secs

$\rule[225]{225}{2}$

Hope this helped!

~AnonymousHelper1807