Answer:
[tex]\huge\boxed{\sf 13 , 15 , 17}[/tex]
Step-by-step explanation:
Let x , x+2 and x+4 be the consecutive numbers
Given Condition:
x + x + 2 + x + 4 = 45
3x + 6 = 45
Subtract 6 to both sides
3x = 45 - 6
3x = 39
Dividing both sides by 3
x = 13
So,
The numbers are:
x = 13
x + 2 = 13 + 2 = 15
x + 4 = 13 + 4 = 17
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
Answer:
let the number be n
n+n+2+n+4 =45
3n+6=45
3n+6+6=45-6
3n/3=39/3
n=13
n=13
n+2=13+2
=15
n+4=13+4
=17
13,15,17
Step-by-step explanation:
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