Respuesta :

Answer:

[tex]\huge\boxed{\sf 13 , 15 , 17}[/tex]

Step-by-step explanation:

Let x , x+2 and x+4 be the consecutive numbers

Given Condition:

x + x + 2 + x + 4 = 45

3x + 6 = 45

Subtract 6 to both sides

3x = 45 - 6

3x = 39

Dividing both sides by 3

x = 13

So,

The numbers are:

x = 13

x + 2 = 13 + 2 = 15

x + 4 = 13 + 4 = 17

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AnonymousHelper1807

Answer:

let the number be n

n+n+2+n+4 =45

3n+6=45

3n+6+6=45-6

        3n/3=39/3

             n=13

n=13

n+2=13+2

      =15

n+4=13+4

     =17

13,15,17

Step-by-step explanation:

pliz mark brainliest

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