Question

A sample of calcium bromide contains 0.2 g calcium and 0.8 g bromine by mass. Calculate the empirical formula of calcium bromide.(relative atomic masses: Ca = 40, Br = 80). Show the calculation.

Answer 1

I worked it... Hope this helps

Answer 2

The empirical formula for calcium bromide has been $\rm CaBr_2$.

The empirical formula has been given with the simplest whole number ratio of the chemical formula.

The moles of calcium in calcium bromide has been:

$moles=\dfrac{mass}{mwt}$

$moles_C_a=\dfrac{0.2}{40} \\moles_C_a=0.005$

The moles of bromine in calcium bromide has been:

$moles_B_r=\dfrac{0.8}{80} \\moles_B_r=0.01$

The simplest whole number ratio for Br and Ca has been given by dividing moles of Ca and Br with moles of Ca.

• The simplest whole number of Ca:

$\rm Ca=\dfrac{0.005}{0.005} \\Ca=1$

• The simplest whole number of Br:

$\rm Br=\dfrac{0.01}{0.005} \\Br=2$

From the whole numbers, the empirical formula for calcium bromide has been $\rm CaBr_2$.

For more information about empirical formula, refer to the link:

https://brainly.com/question/1247523