a rectangular parking lot has a lenth that is 6 yard graeter than the width the area of the parking lot is 160 ssquar yardsd. find the lenth and the width use the formulaarea

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Answer:

Required Answer:-

Let

the breadth =x

the length =6x

  • [tex]\sf Area=160yard^2 [/tex]

As we know that in a rectangle

[tex]{\boxed{\sf Area=lb}}[/tex]

  • Substitute the values

[tex]{:}\longrightarrow[/tex][tex]\sf x\times 6x=160 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf 6x^2=160[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x^2={\dfrac {160}{6}}[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x^2=26.6 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x=\sqrt {26.6}[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x=5.1yards[/tex]

  • Length=6\times 5.1=30.6yards
  • Breadth=5.1yards
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