Use the method of ELIMINATION to solve the system. You must SHOW ALL WORK. Make sure you have an answer for both x and y.

X: 4x+8y=20
y: -4x+2y=-30
Thank you.

Respuesta :

Answer:

Required Answer:-

[tex]\sf 4x+8y=10\dots\dots (1)[/tex]

[tex]\sf -4x+2y=-30\dots\dots (2)[/tex]

  • by adding eq (1) and eq (2) we get

[tex]{:}\longrightarrow[/tex][tex]\sf 4x+8y=20 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf -4x+2y=-30 [/tex]

__________________________

[tex]{:}\longrightarrow[/tex][tex]\sf 10y=-10 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf y={\dfrac {-10}{10}}[/tex]

[tex]{:}\longrightarrow[/tex][tex]{\underline{\boxed{\bf y=-1}}}[/tex]

  • Substitute the value in eq (2)

[tex]{:}\longrightarrow[/tex][tex]\sf -4x+2 (-1)=-30 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf -4x-2=-30 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf -4x=-30+2 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf -4x=-28 [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf x={\dfrac {-28}{-4}}[/tex]

[tex]{:}\longrightarrow[/tex][tex]{\underline{\boxed{\bf x=7}}}[/tex]

[tex]\therefore[/tex][tex]{\underline{\boxed{\bf (x,y)=(7,-1)}}}[/tex]

(7,-1) will be you’re answer
ACCESS MORE