Question

What is the solution set for 9x^2-25=0?

Answer 1

Answer:

A

Step-by-step explanation:

9x^2-25=0

x= 5/3 and -5/3

Answer 2

By solving quadratic equation $9x^2-25=0$ we got solution set as $\{\frac{-5}{4}, \frac{5}{4} \}$

What is quadratic equation ?

Any equation that can be written in form as $ax^{2}+bx+c=0$  , where x is variable and a, b and c are any real numbers and  a ≠ 0 is called quadratic equation .

given quadratic equation :

$9x^2-25=0$

Adding 25 both sides

$9x^2-25+25=0+25\\\\\Rightarrow 9x^2=25$

Dividing by 9 on both sides

$\frac{9x^2}{9}=\frac{25}{9}\\\\x^2= \frac{25}{9}$

Taking square root both sides

$x= \pm \sqrt(\frac{25}{9})$

$x= \pm \frac{5}{4}$

$x= \{\frac{-5}{4}, \frac{5}{4} \}$

By solving quadratic equation $9x^2-25=0$ we got solution set as $\{\frac{-5}{4}, \frac{5}{4} \}$

To learn more about quadratic equation visit :https://brainly.com/question/1214333