Respuesta :
9514 1404 393
Answer:
k > 9/20
Step-by-step explanation:
If the parabola does not touch the x-axis, the discriminant is negative. That means ...
b^2 -4ac < 0
(-3)^2 -4(5)(k) < 0
9 < 20k . . . . . . . . . add 20k
k > 9/20 . . . . . . . . .divide by 20
[tex]y=5x^2-3x+k\\[/tex]
Discriminant | D < 0 (Because doesn't intercept any x-values)
[tex]D = (-3)^2-4(5)(k) < 0\\9-20k<0\\-20k<-9\\k>\frac{9}{20}[/tex]
Therefore, the value of k must be greater than 9/20
so k > 9/20