20-11-2020
Mathematics

contestada

Y=1200 x (1+0.3)^t

What is the initial value and what is the rate of growth

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charlielastname101 charlielastname101

20-11-2020

Answer:

initial value is 1200, rate of growth is 0.3

Step-by-step explanation:

A(t) = P(1+r)^t

p= initial value

r= rate of growth

A(t)= amount after

t= time

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