Answer:
p≤1 or p∠-2
Step-by-step explanation:
REMEMBER OUR GOAL IS TO LEAVE P ALONE!!
p≤1:
1. [tex]\frac{3p+5}{2}\geq 4[/tex] Multiply by 2 to cancel out 1/2 which would give you [tex]{3p+5}\geq 8[/tex]
2. Then subtract 5 which would give you 3p≥3
3. Then divide by 3 which will FLIP the ≥ into ≤.
4. Therefore, it's p≤1.
p∠-2:
1. [tex]\frac{p-6}{4}\leq -2[/tex] Multiply by 4 to cancel out the denominator which would give you [tex]p-6[/tex]∠-8
2. Add 6 to both sides which results in p<-2
