Question

Dance dance1 = new Dance("Tango","Hernandos Hideaway");
Dance dance2 = new Dance("Swing","Hound Dog");
System.out.println(dance1.toString());

System.out.println(dance2.toString());

class Dance
{
private String name;
private String song;

public Dance(String name, String s)
{
this.name = name;
song = s;
}

public String toString()
{
return name + " " + song;
}
}
What is printed when the program is executed?


a
null null

null null

b
Hernandos Hideaway null

Hound Dog null

c
null null

Swing Hound Dog

d
Tango Hernados Hideaway

Swing Hound Dog

e
null Hernandos Hideaway

null Hound Dog

Answer 1

Answer:

The output of the program is (d)

Tango Hernados Hideaway

Swing Hound Dog

Explanation:

Analyzing the given code segment

In class Dance,

A method named dance was defined with an instance of two string variables/values

which are name and song

public Dance(String name, String s)

In the main of the program,

The first line creates an instance of Dance as dance1

dance1 is initialized with the following string values: "Tango","Hernandos Hideaway"

- The first string value "Tango" will be passed into the name variable of the Dance method

- The second string value "Hernandos Hideaway" will be passed into the song variable of the Dance method

Next, another instance of Dance is initialized as dance2

dance2 is initialized with the following string values: "Swing","Hound Dog"

- The first string value "Swing" will be passed into the name variable of the Dance method

- The second string value "Hound Dog" will be passed into the song variable of the Dance method

On line 3 of the main: System.out.println(dance1.toString());

The values of dance1, which are "Tango","Hernandos Hideaway" are printed

On line 4 of the main: System.out.println(dance2.toString());

The values of dance1, which are "Swing","Hound Dog" are printed

Hence, option d answers the question