Question

A golf ball is hit at an angle of 45° above the horizontal. What is the acceleration of the golf ball at the highest point in its trajectory? [Neglect friction.] a = m/s2

Answer 1

Answer:

32* acceleration

Explanation:

why? because if the ball is at a 35* angle then it will accelerate 32*

Answer 2

The acceleration of the golf at the maximum height is equivalent to acceleration due to gravity = 9.8 m/s².

The given parameters;

angle of projection of the ball, Ф = 45°

Acceleration is defined as the change in velocity per change in time of motion.

$a = \frac{\Delta v}{\Delta t} = \frac{v_f }{t}$

where;

$v_f$ is the final velocity of the golf

At maximum height the final velocity of a projectile is zero (0)

The acceleration for upward motion becomes;

$a = \frac{0 }{t} + g= g$

Thus, the acceleration of the golf at the maximum height is equivalent to acceleration due to gravity.

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