Answer:
The probability of a pill having more than 24.125 mg active substance is 0.0495.
Step-by-step explanation:
Let X denote the amount of active substance in each pill.
It is provided that,[tex]X\sim N(20,\ 2.5^{2})[/tex]
Compute the probability of a pill having more than 24.125 mg active substance as follows:
[tex]P(X>24.125)=P(\frac{X-\mu}{\sigma}>\frac{24.125-20}{2.5})[/tex]
[tex]=P(Z>1.65)\\\\=1-P(Z<1.65)\\\\=1-0.95053\\\\=0.04947\\\\\approx 0.0495[/tex]
Thus, the probability of a pill having more than 24.125 mg active substance is 0.0495.