Question

The critical resolved shear stress for a metal is 35 MPa. Determine the maximum possible yield strength (in MPa) for a single crystal of this metal that is pulled in tension.

Answer 1

Answer:

The maximum possible yield strength for a single crystal is 70 MPa.

Explanation:

To find the maximum possible yield strength for a single crystal we need to use the following equation:

$\sigma_{y} = \frac{\tau_{CRSS}}{m_{max}}$

Where:

$m_{max}$ is the maximum value for Schmid factor

$\tau_{CRSS}$ is the critical resolved shear stress = 35 MPa

$\sigma_{y}$ is the yield strength =?    

The Schmid factor is given by:

$m = cos(\phi)cos(\lambda)$

And its maximum value is obtained when λ = 45° and Φ = 45°, so:

$m = cos(45)cos(45) = 0.5$

Finally, the maximum possible yield strength is:

$\sigma_{y} = \frac{\tau_{CRSS}}{m_{max}} = \frac{35 MPa}{0.5} = 70 MPa$

Therefore, the maximum possible yield strength for a single crystal is 70 MPa.

I hope it helps you!