Question

Photons of infrared radiation with wavelengths longer than those of visible light will have what kind of energy compared to that of visisble light?

Answer 1

Answer:

Infrared photons carry lower radiation energy than the visible light.

Explanation:

• Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.
• So, we can write the energy of a single photon as follows:

       $E = h*\nu (1)$

• Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.
• So, an infrared photon carries less energy that one of the visible light.

Answer 2

Infrared photons carry lower radiation energy than the visible light.

What are visible and infrared radiation?

Visible light is the section of the spectrum of electromagnetic radiation which are visible to human eyes. The wavelength range of this light varies from 400 nm to 700 nm .

Each photon carries an energy that is directly proportional to its frequency, being this proportionality constant the Planck's constant h.

So, we can write the energy of a single photon as follows:

$E=h\nu$      

Since there exists an inverse relationship between wavelength and frequency, and infrared radiation has longer wavelengths, this means that its frequency is lower than the one of the visible light.

So, an infrared photon carries less energy than one of the visible light.

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