Question

X333: countElements Given an array of integers and an integer target, return a count of the number of times the target value occurs in the array. Examples: countElements((25, 42, 18, 25, 38, 96, 25, 25〉, 25) -> 4 countElements (110, 20, 30, 40, 50, 99)-> θ 1 public int countElements (int[] nums, int target) 2 {34 }5

Answer 1

Answer:

The method written in java is as follows:

public static int countElements(int[] nums, int target){

    int count=0;

    for(int i =0;i<nums.length;i++){

        if(nums[i] == target){

            count++;

        }

    }

    return count;

}

Explanation:

The method definition is not clear in the question you posted; so, I'll answer the question from scratch

This defines the method

public static int countElements(int[] nums, int target){

This initializes count to 0

    int count=0;

This iterates through the array

    for(int i =0;i<nums.length;i++){

This checks if the current array element is same as the target

        if(nums[i] == target){

If yes, the count variable is incremented by 1

            count++;

        }

    }

This returns the count

    return count;

}

See attachment for complete program which includes the main