Question

The orbital diagram shows the valence electrons of sulfur, which has 16 electrons. If the electrons were added to the atom one at a time, which would be the last electron to occupy an orbital?

My question: Is this correct?

Answer 1

Answer:

Its the arrow going down in the 3p level!

Explanation:

Answer 2

The orbital configuration for the 16 atoms of the element Sulphur can be written thus $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{4}$. The last electron to occupy an orbital would be second arrow in the first box of the 3p level.

Each sublevel has to be half filled before taking in a second electron in the p, d and f levels.

Sulphur's last 4 atoms belongs to the 3p level ; which are 3px ; 3py and 3pz. Each of the x, y and z sublevels are given one electron each and the fourth and last electron ls then assigned to the 3px sublevel.

Therefore, the last electron will occupy the first sublevel on the 3p level.

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